24.7k views
2 votes
How many right triangles have a hypotenuse that measures 2x + 3 meters and legs that measure 2x - 5 meters and x + 7 meters? What are their dimensions?

User Alfin Paul
by
8.1k points

1 Answer

5 votes

Answer:

Two right angled triangle are possible.

Explanation:

We are given the following in the question:

Measure of hypotenuse in meters =
2x + 3

Measure of legs in meters =
2x -5 \text{ and }x+7

In a hypotenuse triangle:


(\text{Hypotenuse})^2 = (\text{leg}_1)^2 + (\text{leg}_2)^2

Putting the values, we get,


(2x+3)^2 = (2x-5)^2 + (x+7)^2\\4x^2 + 9+12x = (4x^2 + 25 - 20x) + (x^2 + 49 +14x)\\4x^2 + 9 +12x = 5x^2 -6x +74\\x^2-18x +65 = 0\\x^2 - 13x - 5x + 65 = 0\\x(x-13)-5(x-13) = 0\\(x-13)(x-5) = 0\\x = 13, x = 5

Thus, there are two triangles possible with dimension:

Triangle 1:


\text{Hypotenuse} = 2x + 3 = 2(13) + 3 = 29\\\text{leg}_1 = 2x-5 = 2(13) - 5 = 21\\\text{leg}_2 = x + 7 = 13 + 7 = 20\\

Triangle 2:


\text{Hypotenuse} = 2x + 3 = 2(5) + 3 = 13\\\text{leg}_1 = 2x-5 = 2(5) - 5 = 5\\\text{leg}_2 = x + 7 = 5 + 7 = 12\\

User Chiuki
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories