Question

An airplane is pressurized with air to 660 mmHg . If air is 21% oxygen, what is the partial pressure of oxygen on the plane?

Answer 1

Answer: The partial pressure of oxygen on the plane is 138.6 mmHg

Step-by-step explanation:

To calculate the partial pressure of the gas, we use the equation given by Raoult's law, which is:

`p_(A)=p_T* \chi_(A)`

where,

`p_A` = partial pressure of oxygen gas = ?

`p_T` = total pressure = 660 mmHg

`\chi_A` = mole fraction of oxygen gas = 21 % = 0.21

Putting values in above equation, we get:

`p_(O_2)=660mmHg* 0.21\\\\p_(O_2)=138.6mmHg`

Hence, the partial pressure of oxygen on the plane is 138.6 mmHg