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An airplane is pressurized with air to 660 mmHg . If air is 21% oxygen, what is the partial pressure of oxygen on the plane?

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Answer: The partial pressure of oxygen on the plane is 138.6 mmHg

Step-by-step explanation:

To calculate the partial pressure of the gas, we use the equation given by Raoult's law, which is:


p_(A)=p_T* \chi_(A)

where,


p_A = partial pressure of oxygen gas = ?


p_T = total pressure = 660 mmHg


\chi_A = mole fraction of oxygen gas = 21 % = 0.21

Putting values in above equation, we get:


p_(O_2)=660mmHg* 0.21\\\\p_(O_2)=138.6mmHg

Hence, the partial pressure of oxygen on the plane is 138.6 mmHg

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