Question

I need help solving m(t) = 2(t-1)^2 + 12

Answer 1

The solution is
`2t^(2) -4t+14`

Step-by-step explanation:

The expression is
`m(t)=2(t-1)^(2)+12`

Squaring the binomial using the formula,
`(a-b)^(2)=a^(2)-2 a b+b^(2)`, we get,

`2(t^(2) -2t+1)+12`

Multiplying 2 within the bracket, we have,

`2t^(2) -4t+2+12`

Adding the constant term,

`2t^(2) -4t+14`

Thus, the solution of the expression is
`2t^(2) -4t+14`