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I need help solving m(t) = 2(t-1)^2 + 12

1 Answer

1 vote

The solution is
2t^(2) -4t+14

Step-by-step explanation:

The expression is
m(t)=2(t-1)^(2)+12

Squaring the binomial using the formula,
(a-b)^(2)=a^(2)-2 a b+b^(2), we get,


2(t^(2) -2t+1)+12

Multiplying 2 within the bracket, we have,


2t^(2) -4t+2+12

Adding the constant term,


2t^(2) -4t+14

Thus, the solution of the expression is
2t^(2) -4t+14

User Erison
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