141k views
1 vote
What is the perimeter of the rectangle shown on the coordinate plane, to the nearest tenth of a unit?

What is the perimeter of the rectangle shown on the coordinate plane, to the nearest-example-1

1 Answer

3 votes

Answer:

Perimeter of rectangle = 6√26 or 30.59 units

Explanation:

Let the rectangle ABCD

so, co-ordinate of A= (-6,4) = (x1,y1)

co-ordinate of B= (4,2) = (x2,y2)

co-ordinate of C= (3,-3) = (x3,y3)

co-ordinate of D= (-7,-1) = (x4,y4)

In rectangle ABCD

AB = CD ( opposite sides of rectangle are equal)

and, AD = BC ( opposite sides of rectangle are equal)

Now, using distance formula

AB = √(x2-x1)² + (y2-y1)²

=√(4-(-6))²+ (2-4)²

=√(4+6)² + (-2)²

=√(10)² + (4)

=√100+4

=√104

=2√26 units

so,AB = CD = 2√26 units

again,by using distance formula

BC = √(x3-x2)² + (y3-y2)²

=√(3-4)² + ( -3-2)²

=√(-1)² + (-5)²

=√1 + 25

=√26 units

so, AD = BC =√26 units

Now,

Perimeter of rectangle = 2(length of rectangle+breadth of rectangle)

=2(2√26 + √26) (AB =CD = 2√26 units & AD = BC = √26 units)

=2.3√26

=6√26 units

Answer is 6√26 or 30.59 units

User Ldlchina
by
4.8k points