Question

A particle with charge +1 nC (a nanocoulomb is 1 10-9 C) is located at the origin. What is the electric field due to this particle at a location <0.5, 0, 0> m?

Answer 1

`E=35.97(V)/(m)`

Step-by-step explanation:

The electric field of a point charge can be calculated using the next equation:

`E=(1)/(4\pi \epsilon_0) (Q)/(r^2)`

Where:

`\epsilon_0=Absolute\hspace{3}permittivity\hspace{3}of\hspace{3}free\hspace{3}space\approx 8.85* 10^(-12) \\Q=Charge\hspace{3}magnitude\\r=Distance`

The distance can be calculated as:

`r=√(0.5^2+0^2+0^2) =0.5`

Using the data provided by the problem:

`E=(1)/(4\pi (8.85* 10^(-12)) ) (1* 10^(-9) )/(0.5^2) =35.96721878\approx35.97V/m`