Answer:
The probability that a repair is made on time and is satisfactory = 0.6545
Explanation:
Let the probability that car is repaired on time be P(Rt) = 0.77
Probability that a car is repaired late, P(Rl) = 1 - P(Rt)
Probability of satisfactory repair = P(S)
Probability of unsatisfactory repair = P(U) = 1 - P(U)
Probability that a repair is satisfactory given that it is made on time, P(S|Rt) = 0.85
P(S|Rt) = (P(S n Rt))/P(Rt)
P(S n Rt) = P(S|Rt) × P(Rt) = 0.85 × 0.77 = 0.6545
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