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PLEASE HELP!

If measurements of a gas are 100L and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe what had to happen to the pressure (if temperature remained constant). Include which law supports this observation. No calculations!

User BertNase
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1 Answer

3 votes

Answer:

P₂ = 450 kiloPascals

Step-by-step explanation:

Boyle's law :))

P₁V₁ = P₂V₂

300*75 = P₂*50

P₂*50= 300*75

P₂ = 300*75/50 = 450

P₂ = 450 kiloPascals

The weight has expanded because of pressure of gas.

User SLN
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