Question

THIS IS URGENT I NEED HELP ASAP.(9x 10^-3)^2

simplify. write in scientific notation
a 8.1x10^-5
b 81x10^-4
c 81x10^-3
d 8.1x10^-6
Evaluate 1/2a^-4b^2 for a =-2 and b=4
a2
b 1/2
c3
d4
is the following statement always, never, or sometimes true?
a number raised to a negative exponent is negative?
A always
B never
C sometimes

Answer 1

C. sometimes

Explanation:

Answer 2

(9x 10^-3)^2=
`(81x^(2))/(1000000)`, so d 8.1x10^-6

Evaluate 1/2a^-4b^2 for a =-2 and b=4

`(1)/(2) (-2)^(-4) *4^(2)\\\\(1)/(2) *(1)/((-2)^(4)) *4^(2)\\\\(1)/(2) *(1)/(2^(4))*4^(2)\\\\(1)/(2) *(1)/(16)*4^(2)\\\\(1)/(2) *(1)/(16)*16=(1)/(2)`

A number raised to a negative exponent is sometimes negative.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)

- Cutiepatutie ☺❀❤