Question

Someone help me with this. I forgot my notes in class

Answer 1

Explanation:

`In\: \triangle ABC\\\\</p><p>BA = BC... (Given) \\\\</p><p>\therefore \angle BAC = \angle BCA \\(Angles \:opposite\: to \:equal\:\\sides\:are\: equal) \\\\</p><p>\because m\angle BCA= 8x... (Given) \\\\</p><p>\therefore \angle BAC = 8x\\\\</p><p>In\: \triangle ABC\\\\</p><p>m\angle ABC + m\angle BAC + m\angle BCA \\= 180\degree \\\\</p><p>\therefore \: 44x + 8x + 8x = 180\degree \\\\</p><p>\therefore \: 60x= 180\degree \\\\</p><p>\therefore \: x= (180\degree)/(60) \\\\</p><p>\therefore \: x= 3\degree\\\\</p><p>\therefore \: m\angle B =44x = 44* 3\degree\\\\</p><p>\therefore \: m\angle B =132\degree\\\\</p><p>m\angle A= m\angle C=8x =8 * 3\degree\\\\</p><p>\therefore \: m\angle A= m\angle C= =24\degree`

Answer 2

see explanation

Explanation:

Since AB = BC the the triangle is isosceles and thus

∠ A = ∠ C = 8x

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180

44x + 8x + 8x = 180, that is

60x = 180 ( divide both sides by 60 )

x = 3

Thus

∠ A = ∠ C = 8x = 8(3) = 24°

∠ B = 44x = 44(3) = 132°