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(X^4/6y)^-2 (y-2/4x-1)^3

User Hira
by
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1 Answer

3 votes

Answer:

{x,y} = {1/3,1/9}

Explanation:

Solution :

{x,y} = {1/3,1/9}

System of Linear Equations entered :

[1] 4x + 6y = 2

[2] -4x + 3y = -1

Graphic Representation of the Equations :

6y + 4x = 2 3y - 4x = -1

Solve by Substitution :

// Solve equation [2] for the variable y

[2] 3y = 4x - 1

[2] y = 4x/3 - 1/3

// Plug this in for variable y in equation [1]

[1] 4x + 6•(4x/3-1/3) = 2

[1] 12x = 4

// Solve equation [1] for the variable x

[1] 12x = 4

[1] x = 1/3

// By now we know this much :

x = 1/3

y = 4x/3-1/3

// Use the x value to solve for y

y = (4/3)(1/3)-1/3 = 1/9

Solution :

{x,y} = {1/3,1/9}

User Giorgos Tsakonas
by
6.9k points