Question

The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions of the rectangle.

Answer 1

Width = 5.5yd

Length = 12yd

Step-by-step explanation:

Area of rectangle =
`66yd^(2)`

Let width of the rectangle = b ,

So, length = 2b+1

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

`66yd^(2) = (2b+1) X b\\66yd^(2) = 2b^(2) + b\\2b^(2) +b-66 = 0\\`

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,

Width = 5.5yd

Length = 12yd