Question

Need help with this and need to show all work.

Answer 1

Explanation:

6) ∆ ABC is similar to ∆ CDE. This means that

Angle B = angle D

Therefore,

8x + 16 = 120

Subtracting 16 from the left hand side and the right hand side of the equation, it becomes

8x + 16 - 16 = 120 - 16

8x = 104

Dividing the left hand side and the right hand side of the equation by 8, it becomes

8x/8 = 104/8

x = 13

7) ∆ ABC is similar to ∆ XYZ. It means that

AB/XY = BC/YZ = AC/XZ

Therefore

11/22 = AC/32

22AC = 32 × 11 = 352

AC = 352/22 = 16

The factor is 2

Therefore,

BC = 44/2 = 22

Perimeter of ∆ABC = 22 + 16 + 11 = 49

Answer 2

The answer to your question is 6.- x = 13 7.- Perimeter = 49

Explanation:

6.- If the triangles are similar then their angles measure the same

8x + 16 = 120

8x = 120 - 16

8x = 104

x = 104/8

x = 13

7.- Use proportions to find the length of the other sides

`(AC)/(AD) = (XZ)/(XY)`
`(AC)/(11) = (32)/(22)` AC = 11
`(32)/(22)`

AC = 16

`(BC)/(11) = (44)/(22)` BC =
`11 (44)/(22)`

BC = 22

Find the perimeter

Perimeter = AB + BC + AC

= 11 + 22 + 16

= 49