Question

. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temperature, what will be the resulting pressure of the air inside? 5.0

Answer 1

The answer to your question is Pressure = 5 atm

Step-by-step explanation:

Data

Volume 1 = V1 = 0.5 l

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

V1P1 = V2P2

Solve for P2

P2 = V1P1/V2

Substitution

P2 = (0.5 x 1) / 0.1

Simplification

P2 = 0.5/0.1

Result

P2 = 5 atm