Question

64 Power is equal to 1 upon 256 ki power B then find 3A + 4b = ?​

Answer 1

Explanation:

`{64}^(A) = (1)/(256^(B) ) \\ \\ \therefore \: {2}^(6A) = (1)/(2^(8B) ) \\ \\ \therefore \: {2}^(6A) = 2^( - 8B) \\ \\ \therefore \: 6A = - 8B \\ \\ \therefore \: 6A + 8B = 0 \\ \\ \therefore \: 2(3A + 4B) =0 \\ \\ \therefore \: 3A + 4B =0`