Question

um fazendeiro comprou a mesma quantidade de bezerros e vacas por 476.000. pagou 800 por um bezerro e 2000 por uma vaca,quantos animais de cada espécie ele comprou?

Answer 1

• The farmer bought 170 animals of each species.

Explanation:

The translation of the question into English is:

"a farmer bought the same number of calves and cows for 476,000. He/she paid 800 for a calf and 2000 for a cow, how many animals of each species did he/she buy?"

Solution to the problem

1. Choose the variable's name and translate the verbal statements into algebraic expressions:

• a) number of calves or cows: x

• b) He/she paid 800 for a calf: 800x

• c) He/she paid 2,000 for a cow: 2000x

• d) For 476,00: 800x + 2000x = 476,000 . . . . this is your equation

2. Solve the equation:

a) Write the equation:

`800x+2,000x=476,000`

b) Add like terms:

`2,800x=476,000`

c) Use division property of equalities: divide both sides by 800:

`x=476,000/2,800=170`

d) Translate the solution into a verbal statement:

Since x represents both the number of calves and the number of cows, the answer is:

• The farmer bought 170 animals of each species.