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Need help doing this, show steps if you could-example-1

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Answer:

p = (0.5 , 5)

Explanation:

D(-6 ,4) E(7 ,6)

For the line FP to be a median, the point p must have the intermediate value at x and at y between points D and E

p = (Dx + Ex)/2 , (Dy + Ey)/2

p = (-6 + 7)/2 , (4 + 6)/2

p = 1/2 , 10/2

p = (0.5 , 5)

This is because for a medium to be the point p has to be right in the middle of the other 2 vertices

User Abhishek Sachan
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