Answer:
222.5g of oxygen
Step-by-step explanation:
Percentage composition of water in 18g (molar mass) is
Hydrogen = 11%
Oxygen = 89%
Molar mass of water (H₂O) = [(1*2) + (16*1)] = 18g/mol
In 18g H₂O 11% of hydrogen is
11 / 100 = x / 18
x = (11*18) /100
x = 1.98g
1.98g of hydrogen is present in 18g of H₂O
89% of oxygen in 18g of H₂O
(89 / 100) = y / 18
y = (89*18) / 100
y = 16.02g
16.02g of O is present in 18g of H₂O
y g of O will be present in 250g of H₂O
y = (250*16.02) / 18
y = 222.5g of oxygen
222.5g of oxygen is present in 250g of water