Question

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. The player began counting at 0 seconds, even though the video had already played 190

frames. The video plays 25 frames per second.
How many frames had the video already played when the time was equal to [- 3 2/5] seconds?

Answer 1

105 frames

Explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames

Answer 2

105 frames.

Explanation:

The rate of the video play is

• 25 frames per second.

First, we need to transform the mixed number into a fraction

`3(2)/(5)sec=(17)/(5)sec`

Now, using the rate, we can find the number of frames after 17/5 seconds

`25 frames/second((17)/(5)sec )=85 \ frames`

But, according to the problem, at 0 seconds, the video had already played 190 frames, so we need to find the difference

`190 - 85 = 105 \ frames`

Therefore, the total number of frames after 3 2/5 seconds is 105.