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Sonya had 20 minutes to do a three-problem quiz. She spent 10 9 10 minutes on question A and 6 3 5 minutes on question B. How much time did she have left for question C?

User PavoDive
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1 Answer

5 votes

Answer: she has 2 5/10 minutes left for question C

Explanation:

Total time that Sonya has for the three-problem quiz is 20 minutes.

She spent 10 9/10 minutes on question A. Converting 10 9/10 minutes to improper fraction, it becomes 109/10 minutes.

She spent 6 3/5 minutes on question B. Converting 6 3/5 minutes to improper fraction, it becomes 33/5 minutes.

Total time spent on question A and question B is

109/10 + 33/5 = (109 + 66)/10

= 175/10 minutes

The amount of time that she has left for question C would be

20 - 175/10 = (200 - 175)/10

= 25/10 = 2 5/10 minutes

User Jyablonski
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