Answer:
Explanation:
Let a represent the charges made hourly by Mechanic 1 and b represent that of Mechanic 2;
a + b = 165, a = 165 - b
10a + 5b = 1200
substitute the value of a in the second equation;
10(165 - b) + 5b = 1200
1650 - 10b +5b = 1200
1650 - 5b = 1200
-5b = 1200 - 1650
-5b = -450
b = 450/5
b = $90/hr
If mechanic 2 charged $90/hr,
a + 90 = 165
a = 165 - 90
a = $75/hr being the hourly rate charged by mechanic 1.