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The atmosphere is about 21% oxygen. At a pressure of 749 torr, what is the partial pressure of O2?

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Answer:

157.29 Torr

Step-by-step explanation:

This question may be solved by the mole fraction.

Mole fraction → Moles of gas / Total moles = Partial pressure of gas / Total pressure

If the atmosphere is about 21% you assume that the mole fraction is 0.21 so:

0.21 = Partial pressure of gas / Total pressure

0.21 = Partial pressure of gas / 749 Torr

Partial pressure of the gas = 749 Torr . 0.21 → 157.29 Torr

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