Answer:
The equation that can be used to find the distance (d), the train will travel in any number of minutes (m) is d=0.12m
Explanation:
we know that
distance =

From the table below
CASE 1:
When time is 5 minutes and distance is 0.6 miles
Speed =

Speed =

speed = 0.12
CASE 2:
When time is 8 minutes and distance is 0.96 miles
Speed =

Speed =

speed = 0.12
CASE 3:
When time is 11 minutes and distance is 1.32 miles
Speed =

Speed =

speed = 0.12
CASE 4:
When time is 14 minutes and distance is 1.68 miles
Speed =

Speed =

speed = 0.12
CASE 5:
When time is 17 minutes and distance is 2.04 miles
Speed =

Speed =

speed = 0.12
CASE 6:
When time is 20 minutes and distance is 2.4 miles
Speed =

Speed =

speed = 0.12
In all the cases we get the speed as 0.12
Hence the equation can be
d = 0.12 m
where d is the distance(in miles) and m is the time(in minutes)