Question

A typical carbon monoxide detector will sound it's alarm if it detects 0.050 g of CO, HOw many molecules of carbon monoxide are need to sound the alarm

Answer 1

Approximately 1.07 x 10^21 molecules of carbon monoxide are needed to sound the alarm in a typical carbon monoxide detector.

Step-by-step explanation:

A typical carbon monoxide detector will sound its alarm if it detects 0.050 g of CO. To determine the number of molecules of carbon monoxide needed to sound the alarm, we need to convert the mass of carbon monoxide to moles and then convert moles to molecules. The molar mass of carbon monoxide is 28.01 g/mol.

First, we calculate the number of moles of carbon monoxide:

moles = mass / molar mass = 0.050 g / 28.01 g/mol = 0.00178 mol

Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules:

molecules = moles x Avogadro's number = 0.00178 mol x 6.022 x 10^23 molecules/mol ≈ 1.07 x 10^21 molecules

Therefore, approximately 1.07 x 10^21 molecules of carbon monoxide are needed to sound the alarm in a typical carbon monoxide detector.

Answer 2

1.07×10²¹ molecules are needed to sound the alarm

Step-by-step explanation:

Let's convert the mass of CO to moles, to determine the amount of molecules.

0.05 g . 1 mol / 28 g = 1.78×10⁻³ moles

Now we can determine the number of molecules with the NA

1 mol has 6.02×10²³ molecules

1.78×10⁻³ moles may have (1.78×10⁻³ . 6.02×10²³) / 1 = 1.07×10²¹ molecules