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An electric field of 11.2 N/C directed due north is superposed on an existing electric field of 16.3 N/C directed due east. What is the magnitude of the resultant field

User Uhura
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1 Answer

3 votes

Answer:

The vector sum of the individual electric filed is 19.8 N/C

Step-by-step explanation:

The principle of superposition states that every charge in space creates an electric field at point independent of the presence of other charges in that medium.

The resultant electric field is a vector sum of the electric field due to individual charges.

Let the electric field directed due north = N

Also, Let the electric field directed due east = E

then the resultant field = R

Given;

An electric field directed due north, N = 11.2 N/C

R² = N² + E²

R = √(N² + E²)

R = √(11.2² + 16.3²)

R = 19.8 N/C

Therefore, the vector sum of the individual electric filed is 19.8 N/C

User Abhishek Ranjan
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