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A 8-sided die is rolled twice. If the same number comes up both times we say that "doubles" was rolled. If at least one 3 was rolled, what is the probability that doubles was roll

User Peaceful
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3 votes

Answer:


(1)/(15)

Explanation:

A 8-sided die is rolled twice and at least one 3 was rolled. So, the total possible outcomes are

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(3,7),(3,8),(1,3),(2,3),(4,3),(5,3),(6,3),(7,3),(8,3)

If the same number comes up both times we say that "doubles" was rolled.

Total favorable outcomes = {3,3}

Total number of favorable outcomes = 1

We need to find the probability that doubles was roll.


Probability=\frac{\tex{Favorable outcomes }}{\text{Total outcomes}}


Probability=(1)/(15)

Therefore, the probability that doubles was roll is
(1)/(15).

User Greycrow
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