Question

Find the equation of the line that goes through the points (-6,-2) and (-3,-6)

Answer 1

y+2=-4/3(x+6)

Explanation:

m=(y2-y1)/(x2-x1)

m=(-6-(-2))/(-3-(-6))

m=(-6+2)/(-3+6)

m=-4/3

y-y1=m(x-x1)

y-(-2)=-4/3(x-(-6))

y+2=-4/3(x+6)