Question

A population has two alleles for a particular gene, A and a, and is in Hardy-Weinberg equilibrium. The frequency of allele a is 0.2. What is the frequency of individuals with AA genotype?

Answer 1

0.64

Step-by-step explanation:

The frequency of an allele is a measure of the relative frequency of that allele on a genetic locus in a population expressed as a fraction or a percentage.

According to Hardy-Weinberg equation, p + q = 1 where p represents allele A and q represents allele a. If the frequency of allele a is 0.2.

Hence, 0.2 + p = 1; p = 1 - 0.2 = 0.8

Therefore, the frequency of allele A is 0.8

Genotype frequency of the homozygous genotype AA is represented by p^2 = (0.8)^2 = 0.64