Question

In the figure, assume that angles that appear to be right angles are right angles

What is the area of the figure
Use 3.14 for PI
Enter your answer in the box

Answer 1

Answer:
`71.13\ units^2`

Explanation:

The area of the figure is the sum of the area of the semi-circle and the area of the trapezoid.

1.The area of the semi-circle can be found with this formula:

`A_(sc)=(\pi r^2)/(2)`

Where "r" is the radius.

In this case you can see that:

`r=3`

Therefore, its area is (Using 3.14 for
`\pi`):

`A_(sc)=((3.14)( 3\ units)^2)/(2)=14.13\ \ units^2`

2.The area of the trapezoid can be found with:

`A_t=(h(B+b))/(2)`

Where "h" is the height and "B" and "b" are the lenghts of the bases.

In this case:

`h=6\ units\\\\B=11\ units\\\\b=8\ units`

Then. its area is:

`A_t=((6)(11+8))/(2)=57\ units^2`

3. Adding those areas, you get that the area of the figure is:

`A_f=14.13 \ units^2+57\ units^2=71.13\ units^2`