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What is the are of the figure which consists of a triangle and two parallelograms?

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What is the are of the figure which consists of a triangle and two parallelograms-example-1
User Zellyn
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The given figures area is found to be 78 square units.

Explanation:

Step 1; To determine the area of an indefinite shape we must divide it into the shapes that we know. The shape that is given can be split into a triangle, a rectangle, and a parallelogram.

Step 2; To determine the area occupied by a different shape, we must sum the areas of the three shapes. Any given triangles area is half the multiplication of its base value and its height value. In the given diagram, the base length of the triangle measures a length of 8 units (same as the rectangle's length) and the length from base to the top is 7 units.

Area of the Triangle =
(1)/(2)* base * height =
(1)/(2) * 8 feet * 7 feet = 28 square units.

The given rectangle measures a length of 8 units and a width of 3 units. The area of any given rectangle is the multiplication of its length and width. Area of the Rectangle = Length * Width = 8 feet * 3 feet = 24 square units.

The formula used to determine the area of any parallelogram and to determine the area of any rectangle is the sameone used. Since this parallelogram has the same dimensions, a length of 8 units and a height equals 3 units. Area of the given parallelogram = 24 square units

Step 3; To find the total area of the shape we must add the areas of the triangle, the rectangle, and the parallelogram. Area of given shape = Area of the triangle + Area of the rectangle+Area of the parallelogram

Area of given shape = 28 + 24 + 24 = 76 square units.

User Quentin Grisel
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