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Determine which score corresponds to the higher relative position. Which is better, a score of 92 on a test with a mean of 71 and a standard deviation of 15, or a score of 688 on a test with a mean of 493 and a standard deviation of 150?

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Answer:

The score of 92 on a test with a mean of 71 and a standard deviation of 15 is better.

Explanation:

To find which score corresponds to the higher relative position, we find the Z-score of each score.

The z-score, which measures how many standard deviation a measure is above or below the mean, is given by the following formula:


Z = (X - \mu)/(\sigma)

In which X is the score,
\mu is the mean and
\sigma is the standard deviation.

A score of 92 on a test with a mean of 71 and a standard deviation of 15.

So
X = 92, \mu = 71, \sigma = 15


Z = (X - \mu)/(\sigma)


Z = (92 - 71)/(15)


Z = 1.4

A score of 688 on a test with a mean of 493 and a standard deviation of 150.

So
X = 688, \mu = 493, \sigma = 150


Z = (X - \mu)/(\sigma)


Z = (688 - 493)/(150)


Z = 1.3

Which is better?

Due to the higher z-score, the score of 92 on a test with a mean of 71 and a standard deviation of 15 is better.

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