Question

The heaviest edible mushroom ever found (the so-called "chicken of the woods") had a mass of 45.4 kg. Suppose such a mushroom is attached to a rope and pulled horizontally along a smooth stretch of ground, so that it undergoes a constant acceleration of +2.9 m/s2. If the mushroom is initially at rest, what will its velocity be after it has been displaced +95 m?

Answer 1

The answer to your question is vf = 23.47 m/s

Step-by-step explanation:

Data

a = 2.9 m/s²

vo = 0 m/s

d = 95 m

vf = ?

Formula

vf² = vo² + 2ad

Substitution

vf² = (0)² + 2(2.9)(95)

Simplification

vf² = 2(275.5)

vf² = 551

vf =
`√(551)`

vf = 23.47 m/s

The mushroom will have a velocity of 23.47 m/s after it has been displaced 95 m.