Answer:
The answer to your question is 1.17 m/s
Step-by-step explanation:
Data
mass of mouse = m1 = 5g
mass of sandwich = m2 = 8 g
initial speed of mouse = U1 = ?
initial speed of sandwich = U2 = 0 m/s
final speed of mouse and sandwich = v = 0.45 m/s
Formula
m1U1 + m2U2 = m1v + m2v
factor v
m1U1 + m2U2 = v(m1 + m2)
Substitution
5U1 + 8(0) = 0.45(5 + 8)
Simplification
5U1 = 0.45(13)
5U1 = 5.85
U1 = 5.85/5
U1 = 1.17 m/s