Angle A measures 120°.
Explanation:
Step 1; Summing all the angles in a quadrilateral equals 360°. So the sum of angles A, B, C, and D will equal 360°. It is given that angle A is half the sum of angles B, C, D. Assume angle B =x, angle C = y, angle D = z.
Angle A = x+y+z / 2, take this as equation 1.
Step 2; Since ABCD is a quadrilateral,
x+y+z = 360, take this as equation 2.
Substituting equation 1 in 2, we get
(x+y+z)/2 + x+y+z = 360°,
Multiply 2 on the LHS due to LCM
(x+y+z) + 2 × (x+y+z) = 360°,
[(x+y+z)+ 2 × (x+y+z)]/2 = 360°.
So we get a denominator of 2 on the LHS, so we multiply the entire equation by 2,
3 × (x+y+z) = 360 × 2 = 720,
(Angle B + Angle C + Angle D) = 720 / 3 = 240.
So Angle B + Angle C + Angle D = 240,
Angle A is half 240°, So angle A equals 240°/2 = 120°.