Spring constant is 200 N/m
Step-by-step explanation:
We have force in a spring
F = kx
k is spring constant and x is elongation of spring.
We have an unstretched spring has a length of 10 centimeters. When the spring is stretched by a force of 16 newtons, its length is increased to 18 centimeters
Force, F = 16 N
Elongation, x = 18 - 10 = 8 cm = 0.08 m
Substituting in
F = kx
16 = k x 0.08
k = 200 N/m
Spring constant is 200 N/m