Question

A 8.01-nC charge is located 1.87 m from a 4.50-nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.(b) Is the force attractive or repulsive?

Answer 1

Step-by-step explanation:

Given

`q_1=8.01\ nC`

`q_2=4.50\ nC`

distance between the charges is given by
`d=1.87\ m`

Electrostatic force between the charges is given by

`F_(12)=F_(21)=(kq_1q_2)/(d^2)`

where k=constant
`=9* 10^(9)`

`F_(12)=F_(21)=(9* 10^9* 8.01* 4.50* 10^(-18))/((1.87)^2)`

`F_(12)=F_(21)=92.769* 10^(-9)\ N`

as both the charges are of similar nature therefore they repel each other