Question

The period of a simple pendulum in a grandfather clock on another planet is 1.80 s. What is the acceleration due to gravity (in m/s2) on this planet if the length of the pendulum is 1.00?

Answer 1

12.17 m/s²

Step-by-step explanation:

The formula of period of a simple pendulum is given as,

T = 2π√(L/g)........................ Equation 1

Where T = period of the simple pendulum, L = length of the simple pendulum, g = acceleration due to gravity of the planet. π = pie

making g the subject of the equation,

g = 4π²L/T²................... Equation 2

Given: T = 1.8 s, l = 1.00 m

Constant: π = 3.14

Substitute into equation 2

g = (4×3.14²×1)/1.8²

g = 12.17 m/s²

Hence the acceleration due to gravity of the planet = 12.17 m/s²