Answer:
The answer to your question is F = 4.17 x 10²³ N
Step-by-step explanation:
Data
mass of the Sun = 2 x 10³⁰ kg
mass of Jupiter 1.9 x 10²⁷ kg
distance = 7.8 x 10¹¹ m
F = ? N
G = 6.67 x 10⁻¹¹ Nm²/kg²
Formula
F = G
![(m1 x m2)/(r^(2))](https://img.qammunity.org/2021/formulas/physics/college/gg3w06p7psqo7c6qwr8sysolqmws9uyblp.png)
Substitution
F = (6.67 x 10⁻¹¹)
![((2 x 10^(30)1.9x 10^(27)))/((7.8 x 10^(11))^(2))](https://img.qammunity.org/2021/formulas/physics/college/8cb5nuga5ypb3hobwmmbsel9jr9dzstw6x.png)
Simplification
F = 6.67x 10⁻¹¹
![(3.8 x 10^(57))/(6.084 x 10x^(23))](https://img.qammunity.org/2021/formulas/physics/college/l9jbglvvlh0i7xxbhpegz67ajxf3v2sy96.png)
F = 6.67 x 10⁻¹¹ (6.245 x 10³³)
Result
F = 4.17 x 10²³ N