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Find the product of -3x^3+2x-4 and x^3+x-2​

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Answer:


-3x^6-x^4+2x^3+2x^2-8x+8

Explanation:

we have


(-3x^(3)+2x-4)(x^(3)+x-2)

Applying distributive property


(-3x^3)(x^3)+(-3x^3)(x)+(-3x^3)(-2)+(2x)(x^3)+(2x)(x)+(2x)(-2)+(-4)(x^3)+(-4)(x)+(-4)(-2)

Remember the properties


(-1)(-1)=(+1)\\(-1)(+1)=(-1)


x^(m)x^(n)=x^(m+n)

so


(-3x^6)+(-3x^4)+(6x^3)+(2x^4)+(2x^2)+(-4x)+(-4x^3)+(-4x)+(8)

Combine like terms


-3x^6-x^4+2x^3+2x^2-8x+8

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