Question

One cylinder has a volume that is 8 Centimeters cubed less than StartFraction 7 over 8 EndFraction of the volume of a second cylinder. If the first cylinder’s volume is 216 Centimeters cubed, what is the correct equation and value of x, the volume of the second cylinder?

Answer 1

7/8X-8=216 x=256

Explanation:

7/8x-8=216

+8 +8

7/8x=224

7/8 7/8

x=256

Answer 2

The correct equation is:

`216 = (7)/(8) * x - 8`

The volume of second cylinder is 256 centimeter cubed

Solution:

Given that,

One cylinder has a volume that is 8cm less than 7/8 of the volume of a second cylinder

The first cylinder’s volume is 216 centimeter cubed

From given,

Let "x" be the volume of second cylinder

Therefore,

Volume of first cylinder = 7/8 of the volume of a second cylinder - 8

`216 = (7)/(8) * x - 8`

`216 = (7x)/(8)-8\\\\216 = (7x-64)/(8)\\\\7x - 64 = 8 * 216\\\\7x - 64 = 1728\\\\7x = 1728 + 64\\\\7x = 1792\\\\Divide\ both\ sides\ by\ 7\\\\x = 256`

Thus the volume of second cylinder is 256 centimeter cubed