Question

A compound consists of 0.154 g sodium, 0.238 g chlorine, and 0.322 g oxygen

Answer 1

Empirical Formula = NaClO₃

Step-by-step explanation:

As the question is incomplete so we will assume that the question is asking for finding out the empirical formula of the compound made up of these elements,

Step 1: Calculate Moles of each element as:

Moles (Na) = 0.154 g / 22.99 g/mol = 0.006698

Moles (Cl) = 0.238 g / 35.45 g/mol = 0.006713

Moles (O) = 0.322 g / 16.00 g/mol = 0.02012

Step 2: Calculate mole ratio and simplify it,

Na Cl O

0.006698 0.006713 0.02012

0.006698/0.006698 0.006713/0.006698 0.02012/0.006698

1.00 1.00 3.00

Result:

Empirical Formula = NaClO₃