Question

Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. What speed will put the car on the verge of sliding as it rounds a level curve of 25.5 m radius?

Answer 1

12.6332454263 m/s

Step-by-step explanation:

m = Mass of car

v = Velocity of the car

`\mu` = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

`(mv^2)/(r)=\mu mg\\\Rightarrow v=√(\mu gr)\\\Rightarrow v=√(0.638* 9.81* 25.5)\\\Rightarrow v=12.6332454263\ m/s`

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s