Question

The solid metallic sphere is replaced with a hollow insulating shell of radius a. A charge Q is spread uniformly over the hollow spherical shell. What is the electric field strength inside the hollow shell at r = a/2?

Answer 1

Answer:0

Step-by-step explanation:

It is given that Q charge is uniformly distributed over hollow spherical shell of radius a

It is clear that all the charge is outside the sphere and there is no charge inside the sphere.

Consider a Gauss surface with radius
`r=0.5 a`

`\oint E\cdot ds=(q)/(\epsilon _0)`

`E\cdot 4\pi (0.5a)^2=(0)/(\epsilon _0)`

as there is no charge inside the Gaussian surface

Therefore Electric field is at r=0.5 a