Question

An electron and a proton, starting from rest, are accelerated through an electric potential diff erence of the same magnitude. In the process, the electron acquires a speed ????e, while the proton acquires a speed ????p. Find the ratio ????e/????p.

Answer 1

42.8153054899

Step-by-step explanation:

`m_e` = Mass of electron =
`9.11* 10^(-31)\ kg`

`m_p` = Mass of proton =
`1.67* 10^(-27)\ kg`

`v_e` = Velocity of electron

`v_p` = Velocity of proton

Here the kinetic energy of the system is conserved so

`(1)/(2)m_ev_e^2=(1)/(2)m_pv_p^2\\\Rightarrow (v_e)/(v_p)=\sqrt{(m_p)/(m_e)}\\\Rightarrow (v_e)/(v_p)=\sqrt{(1.67* 10^(-27))/(9.11* 10^(-31))}\\\Rightarrow (v_e)/(v_p)=42.8153054899`

The ratio is 42.8153054899