Option B:
![-4.9t^2+20t+1.2=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x06clptuztgbaocngdiz574w5ez36dcxup.png)
General formula for the height(feet) of a projectile over time:
![h(t)=-16t^2+v_0t+h_0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/urpjzmlhqoipto85g8lh7m1a5e4mr90yii.png)
where h represents height (feet)
t represents time
represents initial velocity
represents initial height(feet)
General formula for the height(metres) of a projectile over time:
![h(t)=-4.9t^2+v_0t+h_0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/uk4vf7280y3gypwp6afis2rgem0rpr7h6u.png)
where h represents height (feet)
t represents time
represents initial velocity
represents initial height(metres)
Given data in the question:
metre
m/s
To determine the equation to find time:
Substitute
and
in general formula for the height(metres) of a projectile over time:
![h(t)=-4.9t^2+20t+1.2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/djenbktxubxckznoj2fytuhyv5qmd9r1s3.png)
![\Rightarrow -4.9t^2+20t+1.2=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wionomiqhmjdflb7bqa3fc1xh8pf6pe2q2.png)
Therefore option B is the correct answer.
![-4.9t^2+20t+1.2=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x06clptuztgbaocngdiz574w5ez36dcxup.png)