Answer & Explanation:
Solutions for given polynomial expressions.
1. f(x) = x3 - x2 + 2x - 2
Bairstow's method divides the polynomial by a quadratic function.
Let initial values p = 0.1 q = 0.1
[0] [1] [2] [3]
a[]
1.0 1.0 2.0 2.0
-0.1 1.11 -2.010004 -2.010004
-0.1 1.11
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b[]
1.0 -1.0 2.010002 -3.191
-0.1 1.100001
-0.1
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c[]
1.0 -11.200001 34.030003
dp = -1.100001 dq = 1.9070003
p = -1.6770535 q = 2.0070002
a[]
1.0 -11.0 32.0 -22.0
2.6770535 -22.280973 20.645508 -15.478039
-2.0070002 16.704155
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b[]
1.0 -8.322947 7.7120266 15.349663
2.6770535 -15.114358
-2.0070002
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c[]
1.0 -5.645893 -9.409331
dp = -1.2019181 dq = 0.9261256
p = -3.8789716 q = 2.9331257
a[]
1.0 -11.0 32.0 -22.0
3.8789716 -27.622267 5.6035914 -4.2372155
-2.9331257 20.886871
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b[]
1.0 -7.1210284 1.4446075 4.4904633
3.8789716 -12.575847
-2.9331257
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c[]
1.0 -3.2420568 -14.064364
dp = -0.35257483 dq = 0.3015399
p = -4.2315464 q = 3.2346656
a[]
1.0 -11.0 32.0 -22.0
4.2315464 -28.641026 0.52601856 -0.4020975
-3.2346656 21.893684
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b[]
1.0 -6.7684536 0.124308825 0.41970253
4.2315464 -10.735041
-3.2346656
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c[]
1.0 -2.5369072 -13.845398
dp = -0.036022577 dq = 0.032922886
p = -4.267569 q = 3.2675886
a[]
1.0 -11.0 32.0 -22.0
4.267569 -28.731113 0.0055390946 -0.004241169
-3.2675886 21.998816
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b[]
1.0 -6.732 0.001 0.004
4.267569 -10.518969
-3.2675886
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c[]
1.0 -2.4648619 -13.785259
dp = -3.8030953E-4 dq = 3.605403E-4
Final solution
p = -4.2679496 , q = 3.267949
Now
-p + Ö(p2- 4q)
root1 = = 3.26
2
-p - Ö(p2- 4q)
root2 = = 1
2
Now the deflated polynomial is
Qn-2(x)* = x - 6.732 Þ root3 = 6.732
*(Qn-2(x) is nothing but the first n-2 elements of b[ ]. )
the roots of the polynomial equation are 3.26, 1.00 and 6.732.