Question

A spherical shell contains three charged objects. The first and second objects have a charge of − 14.0 nC and 33.0 nC , respectively. The total electric flux through the shell is − 953 N ⋅ m 2 / C . What is the charge on the third object?

Answer 1

Step-by-step explanation:

Formula depicting relation between total flux and total charge Q is as follows.

`\phi  = (Q)/(\epsilon_(o))` (Gauss's Law)

Putting the given values into the above formula as follows.

Q =
`\phi * \epsilon_(o)`

=
`-953 Nm^(2)/C * 8.854 * 10^(-12)`

=
`-8.4 * 10^(-9) C`

= -8.4 nC

Therefore, when the unknown charge is q then,

-14.0 nC + 33.0 nC + q = -8.4 nC

q = -27.4 nC

Thus, we can conclude that charge on the third object is -27.4 nC.