Question

A hot air balloon has just lifted off and is rising at the constant rate of 1.60 m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 10.7 m/s. If the passenger is 2.00 m above her friend when the camera is tossed, how much time does it take for the camera to reach her?

Answer 1

Time = 0.187 secs

Step-by-step explanation:

Parameters given:

Speed of hot air balloon = 1.60 m/s

Speed of toss = 10.7 m/s

Distance between passenger and friend at time of toss = 2m

To find the time given, we can simply divide the distance between the passenger and her friend by the speed of the toss. Mathematically,

Time = distance/speed

Time = 2/10.7

Time = 0.187 secs

Therefore, it takes 0.187 seconds for the camera to get to her.