159k views
3 votes
Solve this system of equations to find x and y, please, and explain how you did it:

x+y=8
x^2+y^2=34

User NinjaKC
by
8.8k points

1 Answer

0 votes

Answer:

Explanation:

The system of equations is expressed as

x + y = 8 - - - - - - - - - - - - - -1

x² + y² = 34 - - - - - - - - - - - -2

From equation 1, we would make x to stand alone by subtracting y from the left hand side and the right hand side of the equation. It becomes

x + y - y = 8 - y

x = 8 - y

Substituting x = 8 - y into equation 2, it becomes

(8 - y)² + y² = 34

(8 - y)(8 - y) + y² = 34

64 - 8y - 8y + y² + y² = 34

2y² - 16y + 64 - 34 = 0

2y²- 16y + 30 = 0

Dividing through by 2, it becomes

y² - 8y + 15 = 0

y² - 5y - 3y + 15 = 0

y(y - 5) - 3(y - 5) = 0

y - 5 = 0 or y - 3 = 0

y = 5 or y = 3

Recall, x = 8 - y

x = 8 - 5. or x = 8 - 3

x = 3 or x = 5

User Jiaming
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories