75.8k views
4 votes
A uniform 6.84 m long horizontal beam that weighs 316 N is attached to a wall by a pin connection that allows the beam to rotate. Its far end is supported by a cable that makes an angle of 55◦ with the horizontal, and a 608 N person is standing 1.9 m from the pin. 1.9 m 6.84 m 608 N 316 N R FT 55◦ Find the force FT in the cable by assuming that the origin of our coordinate system is at the rod’s center of mass.

User Atmaram
by
8.8k points

1 Answer

2 votes

Step-by-step explanation:

Let us assume that moment about the pin and then setting it equal to zero as the rod is in equilibrium is as follows.

Moment = Force × Leverage


-F_(T) Sin 55^(o) * 6.84 m + 316 N * (6.84)/(2) m + 608 N * 6.84 m


-F_(T) * 0.81915 * 6.84 m + 316 N * (6.84)/(2) m + 608 N * 6.84 m = 0


F_(T) = 935.11 N

Therefore, we can conclude that the force (
F_(T)) in the cable by assuming that the origin of our coordinate system is at the rod’s center of mass is 935.11 N.

User Astery
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.