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Two conducting spheres of different sizes are at the same potential. The radius of the larger sphere is four times larger than that of the smaller sphere. If a total charge Q is placed on this system, what fraction of Q sits on the larger sphere?(Give your answer as a decimal. For example, if the answer is 1/3 then input 0.333.)

User Debashish
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1 Answer

5 votes

Answer:

0.8

Step-by-step explanation:

The two spheres have the same potential, V.

Let the radius of the larger sphere be R and the radius of the smaller sphere be r,

=> R = 4r

Let the charge on the smaller sphere be q. Hence, the larger sphere will have charge Q - q.

The potential of the smaller sphere will be:


V_S = (kq)/(r)

The potential of the larger sphere will be:


V_L = (k(Q - q))/(R)

Inputting R = 4r,


V_L = (k(Q - q))/(4r)

Since
V_S = V_L = V,


(k(Q - q))/(4r) = (kq)/(r)

=> Q - q = 4q

=> 5q = Q

q = 0.2Q

The fraction of the charge Q that rests on the smaller sphere is 0.2

The charge of the larger sphere is:

Q - q = Q - 0.2Q = 0.8Q

∴ The fraction of the total charge Q that rests on the larger sphere is 0.8

User Jsegal
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